Is actually a finite two-person game of perfect information. Moreover, if we consider draw as victory of White, then by, exactly one of the two has a winning strategy, either Black or White. In other words, either Black is destined to win, if he does not make any error, or White can at least make a draw. So my question is which one? The Black or the White? I have asked a for, however, the terminal answer for board 19$ times$19 is still unknown despite of Black having more or less some advantages. However, for Gomoku there is another story.

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A programmer asserted that Black has a winning strategy in Gomoku(freestyle). Moreover, (s)he announced (s)he had found this winning strategy and written a program named which 'completely terminated the gomoku game'.

Furthermore, (s)he claimed that the one who first beat the program can earn a bonus $￥920000$ (about $€92000$). But no one has taken this bonus since 2006. So there seems to be sufficient reasons to believe (s)he is right. But I still have a doubt: Do PCs nowadays have enough capability to calculate the whole game tree? Unipatch 1c 83 x64 10. So another question arose: Does Gomoku Terminator(v1.22) really have the winning algorithm for Black?

You have chosen to download Gomoku Terminator 1.22. Check the file details to make sure this is the correct program and version, and that your operating. Gomoku Terminator is a little program that computer will sure win if takes black stone,it.

The Wikipedia article you linked to states that L. Victor Allis showed in $1994$ that black wins on a $15 times15$ board. The 'Gomoku Terminator' site you link to has an image of the upper portion of a board with $15$ columns. Thus it seems that this program merely does what was known to be possible in $1994$, and this has no bearing on the open question of the $19 times19$ board. Allis' thesis states that Gomoku used to be played on $19 times19$ boards because that's the size of Go boards, but that the $15 times15$ board has now become the standard.